1.链接地址：

http://poj.org/problem?id=2105

http://bailian.openjudge.cn/practice/2105

2.题目：

IP Address

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 18146		Accepted: 10456

Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:

2

⁷

2

⁶

2

⁵

2

⁴

2

³

2

²

2

¹

2

⁰

128 64  32  16  8   4   2   1

Input

The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

400000000000000000000000000000000 00000011100000001111111111111111 11001011100001001110010110000000 01010000000100000000000000000001

Sample Output

0.0.0.03.128.255.255203.132.229.12880.16.0.1

Source

3.思路：

4.代码：

1 #include "stdio.h" 2 #include "stdlib.h" 3  4 int f(char input[],int start) 5 { 6     int ans=0; 7     int i; 8     for(i=0;i<8;i++) 9     {10        ans=ans*2+(input[i+start]-'0');11     }12     return ans;13 }14 int main()15 {16     int a,b,c,d;17     int n;18     int i;19     char input[34];20     scanf("%d\n",&n);21     for(i=0;i